我就廢話不多說了，大家還是直接看代碼吧~

// 告警排序Collections.sort(domesticAirport, comparator);// 告警排序Comparator<AirportRtWeatherWarningBeanForTable> comparator = new Comparator<AirportRtWeatherWarningBeanForTable>() {@Overridepublic int compare(AirportRtWeatherWarningBeanForTable a1, AirportRtWeatherWarningBeanForTable a2) { // 首先根據是否過期排序 if(a1.isMetarExpired() && !a2.isMetarExpired()){return 1; }else if (!a1.isMetarExpired() && a2.isMetarExpired()) {return -1; } else if ((a1.isMetarExpired() && a2.isMetarExpired()) || (!a1.isMetarExpired() && !a2.isMetarExpired())) {//同時過期，或者都不過期，則按告警類型排序if (a1.getWarningColor() != a2.getWarningColor()) { return compareColor(a1.getWarningColor(), a2.getWarningColor());} } //告警類型相同，按字母排序 return a1.getCode4().compareTo(a2.getCode4()); } }; // 告警類型比較排序 public int compareColor(Color color1, Color color2) { int i = 0; int j = 0; if (color1.equals(MeteoWeatherWarningPanel.RED)) { i = 3; } else if (color1.equals(MeteoWeatherWarningPanel.YELLOW)) { i = 2; } else if (color1.equals(MeteoWeatherWarningPanel.GREEN)) { i = 1; } if (color2.equals(MeteoWeatherWarningPanel.RED)) { j = 3; } else if (color2.equals(MeteoWeatherWarningPanel.YELLOW)) { j = 2; } else if (color2.equals(MeteoWeatherWarningPanel.GREEN)) { j = 1; } int k = i - j; if (k > 0) { return -1; } else if (k < 0) { return 1; } else return 0; }

補充知識：Collections.sort多字段排序-指定排序方式-指定排序字段

看代碼吧~

1、創建需要排序的字段數組

String [] sortNameArr = {“one”, “tow”,“startDate”};

2、為每個字段執行排序規則

boolean[] isAs = {false, false, false};

3、重寫sort方法進行排序

ListUtils.sort(list, sortNameArr, isAs);

public static <E> void sort(List<E> list, final String[] sortnameArr, final boolean[] typeArr) { if (sortnameArr.length != typeArr.length) { throw new RuntimeException('屬性數組元素個數和升降序數組元素個數不相等'); } Collections.sort(list, new Comparator<E>() { public int compare(E a, E b) {int ret = 0;try { for (int i = 0; i < sortnameArr.length; i++) { ret = ListUtils.compareObject(sortnameArr[i], typeArr[i], a, b); if (0 != ret) { break; } }} catch (Exception e) { e.printStackTrace();}return ret; } }); } private static <E> int compareObject(final String sortname, final boolean isAsc, E a, E b) throws Exception { int ret; Object value1 = ListUtils.forceGetFieldValue(a, sortname); Object value2 = ListUtils.forceGetFieldValue(b, sortname); // 兩個字段都不為空進行排序 if (null != value1 && null != value2) { String str1 = value1.toString(); String str2 = value2.toString(); if (value1 instanceof Number && value2 instanceof Number) {int maxlen = Math.max(str1.length(), str2.length());str1 = ListUtils.addZero2Str((Number) value1, maxlen);str2 = ListUtils.addZero2Str((Number) value2, maxlen); } else if (value1 instanceof Date && value2 instanceof Date) { // 日期排序long time1 = ((Date) value1).getTime();long time2 = ((Date) value2).getTime();int maxlen = Long.toString(Math.max(time1, time2)).length();str1 = ListUtils.addZero2Str(time1, maxlen);str2 = ListUtils.addZero2Str(time2, maxlen); } if (isAsc) {ret = str1.compareTo(str2); } else {ret = str2.compareTo(str1); } return ret; } else if (null == value1 && null != value2) { // 比值為空 被比值大 ret = 1; } else { // 被比值為空比值打 ret = -1; } return ret; } public static String addZero2Str(Number numObj, int length) { NumberFormat nf = NumberFormat.getInstance(); // 設置是否使用分組 nf.setGroupingUsed(false); // 設置最大整數位數 nf.setMaximumIntegerDigits(length); // 設置最小整數位數 nf.setMinimumIntegerDigits(length); return nf.format(numObj); } public static Object forceGetFieldValue(Object obj, String fieldName) throws Exception { Field field = obj.getClass().getDeclaredField(fieldName); Object object = null; boolean accessible = field.isAccessible(); if (!accessible) { // 如果是private,protected修飾的屬性，需要修改為可以訪問的 field.setAccessible(true); object = field.get(obj); // 還原private,protected屬性的訪問性質 field.setAccessible(accessible); return object; } object = field.get(obj); return object; }

以上這篇java Collections 排序--多條件排序實例就是小編分享給大家的全部內容了，希望能給大家一個參考，也希望大家多多支持好吧啦網。