1例如：要把如圖1的字段拆分圖2

select account_id, substring_index(substring_index(a.related_shop_ids,’,’ ,b.help_topic_id+1),’,’,-1) shopid from sales_hang_account a join mysql.help_topic b on b.help_topic_id < (length(a.related_shop_ids) - length(replace(a.related_shop_ids,’,’,’’))+1) order by a.account_id

2：然后和shops表進行連接查詢?nèi)〕鑫覀冃枰淖侄危疫@里需要取出name

select s.`name` as shopname,a.account_id from shops sinner JOIN (select account_id, substring_index(substring_index(a.related_shop_ids,’,’ ,b.help_topic_id+1),’,’,-1) shopid from sales_hang_account a join mysql.help_topic b on b.help_topic_id < (length(a.related_shop_ids) - length(replace(a.related_shop_ids,’,’,’’))+1) order by a.account_id)a on s.shop_id=a.shopid

3:將 account_id相同合并成一行，以逗號隔開

//這兩個是網(wǎng)上的例子select ID,group_concat(NAME) as NAME from table group by ID;select ID,group_concat(NAME SEPARATOR ’;’) as NAME from a group by ID;//借助上面兩個參考select account_id,GROUP_CONCAT(shopname SEPARATOR’,’)as shopname from (select s.`name` as shopname,a.account_id from shops sinner JOIN (select account_id, substring_index(substring_index(a.related_shop_ids,’,’ ,b.help_topic_id+1),’,’,-1) shopid from sales_hang_account a join mysql.help_topic b on b.help_topic_id < (length(a.related_shop_ids) - length(replace(a.related_shop_ids,’,’,’’))+1) order by a.account_id)a on s.shop_id=a.shopid) a GROUP BY account_id

效果如下

第二種方法

select g.account_id,g.related_shop_ids,GROUP_CONCAT(s.name)as shopname from sales_hang_account g left join shops s on FIND_IN_SET(s.shop_id , g.related_shop_ids)GROUP BY g.account_id

SqlServer

[Product] -- 該字段存儲格式為 7,8,9,11,10,12 ，數(shù)據(jù)類型為nvarcharselect id,ProductName=stuff((select ’,’ + product_chinaname from base_supplier_product where charindex(’,’+ltrim(productid)+’,’,’,’+ Product + ’,’) > 0 for xml path(’’) ), 1, 1, ’’) FROM base_Pre_sale_project

結(jié)果

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